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The values that make this statement falser are any in which a and b do not have the same sign.
For instance, if a was equal to 3 and b was equal to -3 than see the results.
|a+b|=
|3+-3|=
|0|= 0
Then see the next equation with the same selections
|a|+|b|
|3|+|-3|
3 + 3 = 6
And this would be true no matter which is the negative, as long as there is one negative and one positive.
Answer:
x = 
Step-by-step explanation:
4x-y+2z = 8x+y-4
4x-8x-y+2z = 8x - 8x +y-4
-4x -y +2z= y-4
-4x -y+y +2z = y+y-4
-4x +2z = 2y-4
-4x+2z-2z = 2y-2z-4
-4x = 2y-2z-4
= 
We will conclude that:
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
<h3>
Comparing the domains and ranges.</h3>
Let's study the two functions.
The exponential function is given by:
f(x) = A*e^x
You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:
y > 0.
For the logarithmic function we have:
g(x) = A*ln(x).
As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

So the range of the logarithmic function is the set of all real numbers.
<h3>So what we can conclude?</h3>
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
If you want to learn more about domains and ranges, you can read:
brainly.com/question/10197594
Total = Principal * (1+(rate/n))^n*years
Total = 1,200 * (1.015)^14
Total =
1,200 * <span><span><span>1.2317557307
</span>
</span>
</span>
<span>Total =
1,478.11</span>
Source:
http://www.1728.org/compint3.htm