1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inn [45]
3 years ago
9

How does y vary with x

Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer:  y varies directly as x ", " y varies proportionally as x ", or " y is directly proportional to x . ") This means that as x increases, y increases and as x decreases, y decreases—and that the ratio between them always stays the same.

Step-by-step explanation:

You might be interested in
A company produces fruity drinks that contain a percentage of real fruit juice. Drink A contains 5% real fruit juice and Drink B
Romashka [77]

Answer:

a). 12.5 liters of real fruit juice would be needed to produce 250 liters of Drink A, and 20 liters of real fruit juice would be needed to produce 250 liters of Drink B

b). 0.05aa liters of real fruit juice would be needed to produce aa liters of Drink A, and 0.1bb liters of real fruit juice would be needed to produce bb liters of Drink B  

Step-by-step explanation:

a). Drinks A(250 liters) and Drink B(200 liters)

Total amount of Drink A=250 liters

Real fruit juice=5% of Drink A=(5/100)×250=12.5 liters

12.5 liters of real fruit juice would be needed to produce 250 liters of Drink A

Total amount of Drink B=200 liters

Real fruit juice=10% of Drink B=(10/100)×200=20 liters

20 liters of real fruit juice would be needed to produce 250 liters of Drink B

b). Drinks aa and bb

Total amount of Drink A=aa liters

Real fruit juice=5% of Drink A=(5/100)×aa=0.05aa liters

0.05aa liters of real fruit juice would be needed to produce aa liters of Drink A

Total amount of Drink B =bb liters

Real fruit juice=10% of Drink 10=(10/100)×bb=0.1bb liters

0.1bb liters of real fruit juice would be needed to produce bb liters of Drink B

5 0
4 years ago
Tell whether a triangle can have sides with lengths 6, 10, and 14. ​
erik [133]
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Since 3in, 4in, and 8in. Since 6+14 > 10,6+ 10 > 14, and 10 + 14 > 6, you can form a triangle with the lengths 6m, 14m, and 10m.
8 0
2 years ago
Hurry Please! Which of the following shows the extraneous solution to the logarithmic equation?
Eduardwww [97]

Answer:

the third circle.

Step-by-step explanation:

5 0
3 years ago
Find the measure of the indicated angle. Round to the nearest tenth.
Darya [45]

Answer:

picture??

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the value of x in the following triangle​
ozzi

Answer:

x = 124°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then

x = 180° - (32 + 24)° = 180° - 56° = 124°

4 0
3 years ago
Other questions:
  • A producer charges $500 for a cell phone, but buyers are not buying any cell phones at this price. So at this price, the produce
    11·2 answers
  • Which of the following is used to cut different shapes edges on a wooden cabinet door
    7·2 answers
  • The volume of a cylinder is 4pi x(3) cubic units and its height is x units. Which expression represents the radius of the cylind
    12·2 answers
  • Can someone help me with question 4 please
    12·1 answer
  • In quadrilateral ABCD, AD ∥ BC. What must the length of segment AD be for the quadrilateral to be a parallelogram?
    5·1 answer
  • (Please be clear)
    13·1 answer
  • Which of the following is an example of simple harmonic motion?
    12·1 answer
  • Find the equation for the area, A, of the rectangle with a length of n-5 and a width of n-1.
    6·2 answers
  • A landscaping business is purchasing plants from a nursery to finish a project. It will cost $14 each to buy each tree and $5 ea
    14·1 answer
  • What 9917.14285714 times 7 not using a calculator???
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!