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3 years ago

Someone please help I need this done ASAP

Mathematics

2 answers:

zhuklara [117]3 years ago

5 0

Answer:

x = 9
y = 10

Step-by-step explanation:

Triangle TUR is equilateral and TRS is isosceles. They share same side TR

x + 4 = 13
x = 9

∠URT and ∠TRS are supplementary,

∠URT = 60° as angle of equilateral triangle,

∠RTS ≅ ∠RST (isosceles)

6y*2 = 180 - 60
12y = 120
y = 10

Vinvika [58]3 years ago

4 0

I don’t know can’t see the picture Clearly

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KIM [24]

Answer:

A) Points earned = 15 - 6

B) Sandy didn't make it to the next level since her score was 9 and she needed a minimum of 10

Step-by-step explanation:

To advance to the next level in her game, Sandy must score at least 10 points.

She scores 15 points for correct matches

She scores -6 points for incorrect matches.

A. The amount of points earned by Sandy in the game is the sum of both scores:

points earned = 15 - 6

points earned = 9

B. Unfortunately, Sandy didn't make it to the next level since her score was 9 and she needed a minimum of 10

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3 years ago

If cos theta = 0.3090, which of the following represents approximate values of sin thetha for 0 degrees <90 degrees? A. sin t

artcher [175]

In this question, the given value is

$cos \theta = 0.3090$

And we have to find the value of sin theta and tan theta where theta is in first quadrant .

And in first quadrant, all are positive .

Now we use the formula, which is

$sin \theta = \sqrt{1-cos^2 \theta} = \sqrt{1 - 0.3090^2} = 0.9511$

And tan theta is the ratio of sin theta and cos theta, that is

$tan \theta = \frac{sin \theta}{ cos \theta} = \frac{0.9511}{0.3090} =3.078$

So the correct option is B .

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3 years ago

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write the formula of gravitational force between two bodies of mass 'x'and 'y' kept at a distance 'r'

Rudik [331]

$\huge \orange{F =G.\frac{xy}{r^2}}$

Step-by-step explanation:

Masses of the bodies are x and y

Distance at which they are kept is r

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$\huge \purple{F =G.\frac{xy}{r^2}}$
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2 years ago

Suppose the probability of passing a driving test is 65%. (a) on a certain afternoon 15 people are tested. (i) what is the expec

Len [333]

In this current scenario,
Probability of passing, p = 65% = 0.65
Then,
Probability of not passing, q = 1-p = 1-0.65 = 0.35

Part (a): When 15 people are tested
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This is 65% of the 15 people tested. That is,
Number of people expected to pass = 0.65*15 = 9.75. This is rounded downwards as upward rounding will violate the 65% criteria.
Therefore,
Number of people expected to pass = 9 people.

(ii) Probability that 11 people are expected to pass the test
p(x=11) = [15Cx]*p^x*q^(15-x) = [15C11]*0.65^11*0.35^(15-11) = 0.1792 ≈ 17.92%

Part (b): Teenager determined to pass the test no matter how many times

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This means that he will fail the first and second time. That is,
Probability pf passing the third time = q*q*p = 0.35*0.35*0.65 = 0.079625 = 7.9625%

(ii) Number of trials it takes to pass
This is a case of mathematical expected, E, that it takes before first occurrence of success. Normally,
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3 years ago

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Greeley [361]

Hello :
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subsct in (1) :
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4 years ago

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