Answer:
<em>A) Points earned = 15 - 6</em>
<em>B) Sandy didn't make it to the next level since her score was 9 and she needed a minimum of 10</em>
Step-by-step explanation:
To advance to the next level in her game, Sandy must score at least 10 points.
She scores 15 points for correct matches
She scores -6 points for incorrect matches.
A. The amount of points earned by Sandy in the game is the sum of both scores:
points earned = 15 - 6
points earned = 9
B. Unfortunately, Sandy didn't make it to the next level since her score was 9 and she needed a minimum of 10
In this question, the given value is

And we have to find the value of sin theta and tan theta where theta is in first quadrant .
And in first quadrant, all are positive .
Now we use the formula, which is

And tan theta is the ratio of sin theta and cos theta, that is

So the correct option is B .

Step-by-step explanation:
- Masses of the bodies are x and y
- Distance at which they are kept is r
- When two bodies are of masses x and y are placed at a distance r then the gravitational force acting on them is given as:

- Where G is the gravitational constant.
In this current scenario,
Probability of passing, p = 65% = 0.65
Then,
Probability of not passing, q = 1-p = 1-0.65 = 0.35
Part (a): When 15 people are tested
(i) Number of people expected to pass
This is 65% of the 15 people tested. That is,
Number of people expected to pass = 0.65*15 = 9.75. This is rounded downwards as upward rounding will violate the 65% criteria.
Therefore,
Number of people expected to pass = 9 people.
(ii) Probability that 11 people are expected to pass the test
p(x=11) = [15Cx]*p^x*q^(15-x) = [15C11]*0.65^11*0.35^(15-11) = 0.1792 ≈ 17.92%
Part (b): Teenager determined to pass the test no matter how many times
(i) Probability that he passes the test the third time
This means that he will fail the first and second time. That is,
Probability pf passing the third time = q*q*p = 0.35*0.35*0.65 = 0.079625 = 7.9625%
(ii) Number of trials it takes to pass
This is a case of mathematical expected, E, that it takes before first occurrence of success. Normally,
E = 1/p
Substituting;
E = 1/0.65 = 1.54 ≈ 2
Therefore, at least two trials will be required.
Hello :
<span>3y = x + 6 ...(1)
y – x = 3...(2)
by (2) : y = x+3...(*)
subsct in (1) :
3(x+3) = x+6
3x-x= -9+6
2x= -3
x=-3/2
subsct in (*) : y =-3/2 +3 =3/2</span>