QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles
Answer:
siz tenths its six tenths your welcome
Step-by-step explanation:
X = 11/3 this answer is finding x in this problem
Answer:
1. Transversal y intersects lines m and n; <1 ~= <2 (Given)
2. <1 ~= <3 (Vertical Angles Theorem)
3. <2 ~= <3 (Transitive Property of Congruence)
4. m || n (Converse of Alternate Interior Angles Theorem)
We can then write an equation representing this problem as:
e−1.5mi=5.25mi
Now, add 1.5mi to each side of the equation to solve for e while keeping the equation balanced:
e−1.5mi+1.5mi=5.25mi+1.5mi
e−0=6.75mi
e=6.75mi
The plane's starting elevation was 6.75 miles
Hope this helps!
