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3 years ago

9

There are 30 students on the school's student council. A special homecoming dance committee is to be formed by randomly selectin

g 6 students from student council. How many possible committees can be formed?

1 answer:

Oksana_A [137]3 years ago

7 0

There can be a possible of 5 committees

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Solve for y in the first equation.

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3 years ago

Two months ago, Marty’s dog weighed 3712 pounds. The dog was put on a diet and exercise plan and now weighs 2914 pounds. How muc

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Answer:

Step-by-step explanation:

3712-2914= 798 pounds

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3 years ago

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Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born

NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

$p = \frac{31}{365} = 0.0849$

Group of 20 friends:

This means that $n = 20$

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773$

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

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3 years ago

weeeeeb [17]

Answer:

O is the center of the circle with radius IE(=ID=EF)

Step-by-step explanation:

Join all 3 points D, E, F, forming the triangle DEF.

Let the midpoint of EF be M and the midpoint of ED be N. (first picture)

Join point I to E, D and F.

Since IN is both an altitude and median to triangle EID, then triangle EID is an isosceles triangle, and IE=ID

similarly, we see that IE=IF.

conclusion: IE=ID=EF.

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3 years ago

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Taj has a choice of water, iced tea, or lemonade; with lemon or lime twist; served in a small or large glass. how many more choi

shusha [124]

Answer:

Total number of choices with a straw: 12

Total number of choices without a straw: 12

Total number of choices: 24

Step-by-step explanation:

Taj has a choice of:

water, iced tea, or lemonade (3 options)

with lemon or lime twist (2 options)

served in a small or large glass (2 options)

This made a total of 3*2*2: 12 different choices

if the drink can be served with or without a straw, he choices are doubled, making a total of 2*12 = 24

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3 years ago