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DiKsa [7]
3 years ago
13

Miguel can use all or part of his $25 gift card to make a music purchase. Each song costs $1.50, and there is a $1.00 per accoun

t activation fee. Which inequalities can represent this situation if m is the number of songs he can buy? Check all that apply.
Mathematics
2 answers:
Nataly [62]3 years ago
6 0
1.00 + 1.50m lesss than or equal to 25
Alik [6]3 years ago
4 0

Answer:

1.00+1.50m \leq 25 or m \leq 16

Step-by-step explanation:

Activation Fee = $1.00

Cost of each song = $1.50

Since we are given that he can buy m songs .

So, Cost of m songs = $1.50 m

So, total cost = Activation charge + Cost of m songs = $1.00+$1.50 m

Since we are also given that Miguel can use all or part of his $25 gift card to make a music purchase.

So, the inequality becomes :

1.00+1.50m \leq 25

or

.50m \leq 25-1

1.50m \leq 24

m \leq \frac{24}[1.5}

m \leq 16

Hence the inequality that can represent the situation is 1.00+1.50m \leq 25 or m \leq 16

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The first term of an arithmetic sequence is 14. The 25th term is 206. What is the common difference of the arithmetic sequence?
larisa [96]

an = a1+ d(n-1)

a1 =14

an=206  when n=25

206 = 14 + d (25-1)

206 = 14 + d * 24

subtract 14 from each side

192 = 24d

divide by 24 on each side

d=8

The common difference is 8

3 0
3 years ago
Read 2 more answers
There are two calculus classes at your school classes have a class average of 75.5 the first class as a standard deviation of 10
DENIUS [597]
To compare the two classes, the Coefficient of Variation (COV) can be used.

The formula for COV is this:
C = s / x

where s is the standard deviation and x is the mean

For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)

For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)

The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
8 0
3 years ago
Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,
Dmitry_Shevchenko [17]

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}

now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0

T = \left|-1250e^{-0.04t}\right|^{\infty}_0

T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})

when any number has a power of negative infinity it is 0. because: a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0, like something being divided by a very large number!

T = (-1250(0))-(-1250e^0)

T = 1250

this is the total amount of waste

6 0
3 years ago
-7x - 2y = 14<br><br> 6x + 6y = 18<br><br> x =<br><br> y =
Mrac [35]

Answer:

6(2) + 6(1) = 18

Step-by-step explanation:

6 0
3 years ago
A shop owner increases some prices by 50%.
Dahasolnce [82]
1.5 is correct answer
8 0
3 years ago
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