This kind of exercise can be real drudgery. But it's almost all simple arithmetic, so better you than me. I'll do one of these for you, which will show you how to do the other one.
a). sin · cot / sec
You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].
Then the problem becomes
sin · (cos/sin) / (1/cos) = cos²
Aw shucks, I might as well also set up 'b)' for you:
b). cos · csc / tan
You're supposed to know that [ cosecant = 1/sine ]
and [ tangent = sine/cosine ].
Then the problem becomes
cos · (1/sin) / (sin/cos) = (cos/sin)²
Now simply plug in the given values of cos A and sin A .
And may I compliment you on your nail care !
It is hard to show work for this problem because it very similar to a basic addition or subtraction problem.
Just so you have the answer and how to solve. -27 is the answer. Think about it like 41-14 then add the negative back. But I would strongly suggest not writing that as work because you teacher might get confused about what you are doing
Answer:
Y is equals to negative 1.
Step-by-step explanation:
y = 2x + 3
y =2(-2)+ 3
y =-4+ 3
y=-1
Answer:
1 and 3
Step-by-step explanation:
because 5 and 3 have the same value and since 5 and 1 add up to 90 degrees, 3 and 1 must also add up to 90 degree
60, 45, and 30 are all factors of 5. So,
B. 5 is the answer