Answer:
-4d
Step-by-step explanation:
L.c.m=15
15×2/5(d-10)-2/3×15(d+6)
3×2(d-10)-2×5(d+6)
6(d-10)-10(d+6)
6d-60-10d-60
6d-10d-60-60
-4d-0
-4d
The variance is the total of the squared distances of the given data from the mean.
This can be calculated through the equation,
σ² = summation of X² / N - μ²
where σ² is the variance X's are the data, N is the number of terms, and μ is the mean.
summation of X² = 100² + 100² + 120² + 120² + 180² = 81200
N = 5
μ = (100 + 100 + 120 + 120 + 180) / 5
μ = 124
Substituting these values to the equation for variance,
σ² = (81200/5) - 124² = 864
Thus, the variance is equal to 864.
Set 500 to sum of distances traveled by both cars.
−
4
x
+
7
=
2
Step 1: Subtract 7 from both sides.
−
4
x
+
7
−
7
=
2
−
7
−
4
x
=
−
5
Step 2: Divide both sides by -4.
−
4
x
−
4
=
−
5
−
4
x
=
5
4
