The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).
Therefore, 
t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :
= 0.020908803
The p value is 0.0209
So we reject the null hypothesis and conclude that 
Alexandera=a
imani=i
a is 8 more than i or
a=8+i
the sum of the 2 numbers is 50 or
a+i=50
a=8+i
so subsitute 8+i for a in a+i=50
8+i+i=50
8+2i=50
subtract 8 from both sides
2i=42
divide both sides by 2
i=21
subsiutte into a=8+i
a=8+21
a=29
a=29
i=21
Solution:
Given,
Volume of the-
First cube box=1728 in³
Second cube box=13824in³
We know that volume of cube =a³
So for the first box
a³= 1728 in³
a= 12 in
Now, surface area of the first box
6a²= 6×(12)²
= 864 in²
and for the second box
b³= 13824 in³
b= 24 in
Now, the surface area of the second box
6b²= 6×(24)²
= 3456 in²
Now, the ratio of the surface area of first box to the second box will be
864:3456
=1:4
The surface area of the larger of two boxes is
3456 in²
