Nathan has two types of stamps:

1 answer:

4 0

A. He could use 5 of the 8¢ Stamps
He could use 10 of the 4¢ Stamps

B. You can be sure that you have found all of the possible combinations because those are the only sets of those specific numbers that equals 40¢ 

C. If Nathan used 40¢ worth of stamps in postage, given that 40¢ is all that Nathan is willing to spend, he would have only used the 8¢ variety of the stamps he owns. You can explain this reasoning in the fact that 8 x 5 = 40 and he spends 40¢.

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Two students were given the expression shown to simplify.

navik [9.2K]

<h3>The equivalent expression is 6 + 6x</h3>

Solution:

Given expression is:

9 - (3 - 6x)

We have to find the equivalent expression

Use the distributive property,

a(b + c) = ab + bc

Therefore, from given expression,

$9 - 1(3 - 6x) = 9 - 3 + 6x$

Combine the constants, 9 - 3 = 6

$9 - 1(3 - 6x) = 6 + 6x$

Thus the equivalent expression is 6 + 6x

3 0

3 years ago

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$