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Xelga [282]
3 years ago
5

Televisions are on sale for 40% OFF the original price of $600. After tax (8.5%) is applied, what is the final price?​

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0

First, determine what is 40% of $600. Multiple 40 (as a decimal) by 600.

0.4 x 600 = 240

Therefore, the discount is $240 off $600.

Subtract the two values to find price (before tax): 600 - 240 = 360

So the TV will cost $360 before tax.

The tax is 8.5%. Multiply 8.5 as a decimal by 360 to find the amount of tax added.

0.085 x 360 = 30.6

Add 30.6 and the price before tax to find the final price.

30.6 + 360 = 390.60

Therefore, the final price of the TV is $390.60

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If FE measures 20 centimeters, the approximate area of circle B is what
MAXImum [283]

If FE measures 20 cm, then the area is 314 cm², if BE measure 3.5 cm, then the area is 38.5 cm², if AB measures 11 cm, then the area is 380 cm² and is EF measures 12 cm, then the area is 113 cm².

Area of a circle:

A = π r²

r = 1 /2 of diameter.

FE is the diameter

r = 20 / 2

r = 10 cm

Area of circle using FE:

A =  π ( 10 )² = π × 100 = 314 cm²

BE is a radius:

Area = π × 3.5² = π × 12.25 = 38.465

A = 38.5 cm²

AB is a radius:

Area = π × 11²
A = π × 121

A = 379.94 = 380 cm²

EF is a diameter:

r = 12 / 2 = 6 cm

Area = π × 6²

A = π × 36

A = 113.04 = 113 cm²

Therefore, if FE measures 20 cm, then the area is 314 cm², if BE measure 3.5 cm, then the area is 38.5 cm², if AB measures 11 cm, then the area is 380 cm² and is EF measures 12 cm, then the area is 113 cm².

Learn more about area here:

brainly.com/question/25292087

#SPJ9

Your question was incomplete, Please refer the content below:

1) if FE measures 20 centimeters, the approximate area of circle B is what?

2) if BE measures 3.5 centimeters, the approximate area of circle B is what?

3) if AB measures eleven centimeters, the approximate area of circle B is what

4) If EF measures twelve centimeters, the approximate area of circle B is what?

6 0
1 year ago
For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

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