Y = 4

Four horses are pulling a wagon. Each horse drinks 45000 ml of water each day. How many liters of water will the horses drink in

s2008m [1.1K]

45000 x 4 = 180,000

180,000 * 5 = 900,000 ml in 5 days

1 liter = 1000 ml

900,000 / 1000 = 900 liters of water

3 0

4 years ago

Felix reported that the coldest day on record for his town was five times colder than yesterday, -4 c . What is the temperature

lapo4ka [179]

Answer:

Coldest day on record = -20°C

Step-by-step explanation:

Given:

Yesterday temperature = -4°C

Coldest day on record = 5 times than yesterday

Find:

Coldest day on record

Computation:

Coldest day on record = 5 × Yesterday temperature

Coldest day on record = 5 × (-4)

Coldest day on record = -20°C

3 0

4 years ago

Together, Dien and Jane can eat 2/3 of a pizza in 4 seconds. How long would it take each of them to eat the whole pizza alone if

Nezavi [6.7K]

Answer:

Dien - 15 seconds, Jane - 10 seconds

Step-by-step explanation:

Together:

2/3 of pizza ⇒ 4 seconds
Full pizza ⇒ 4 ÷ 2/3 = 6 seconds

Dien needs x seconds to eat pizza

Jane needs x - 5 seconds to eat pizza

In one second, Dien can eat 1/x, Jane can eat 1/(x - 5), together 1/6 of a pizza

1/x + 1/(x - 5) = 1/6
x(x - 5) = 6(x + x - 5)
x² - 5x - 12x + 30 = 0
x² - 17x + 30 = 0
(x - 15)(x - 2) = 0
x = 15 (x = 2 is discounted as not realistic)

Dien can eat a pizza in 15 seconds, Jane can eat a pizza in 10 seconds

5 0

3 years ago

Who can help with geometry

Kay [80]

Answer:

h = 21.5cm.

Step-by-step explanation:

Step one: Simplify the volume.

220.16 x (pi) = 691.65cm^3.

Step two: Isolate h.

Cylinder volume equation: V = (pi)(r^2)(h), where r is the radius and h is the height.

Divide out the pi and r^2 on both sides to isolate h and move the equation to V/(pi)(r^2) = h.

Step three: Solve for h.

691.65/(pi)(3.2^2) = 21.5cm rounded to the nearest tenths place.

To illustrate this, please check the diagram below.

8 0

3 years ago

Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,

NARA [144]

Answer:

The 98% confidence interval for the mean magnesium ion concentration is between 122 ppm and 220 ppm. As the lower bound of the interval is below 195, it is not reasonable to conclude that the mean magnesium ion concentration may be greater than 195

Step-by-step explanation:

The six measurements are:

202, 164, 157, 177, 113, 213

Sample mean:

Sum of all values divided by the number of values which is 6. So

$S_m = \frac{202+164+157+177+113+213}{6} = 171$

Sample standard deviation:

Square root of the difference squared between each value and the mean, and divided by 1 subtracted by the sample size. So

$s = \sqrt{\frac{(202-171)^2+(164-171)^2+(157-171)^2+(177-171)^2+(113-171)^2+(213-171)^2}{5}} = 35.69$

Confidence interval

We have the standard deviation for the sample, which means that the t-distribution will be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 3.365

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 3.365\frac{35.69}{\sqrt{6}} = 49$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 171 - 49 = 122 ppm

The upper end of the interval is the sample mean added to M. So it is 171 + 49 = 220 ppm

The 98% confidence interval for the mean magnesium ion concentration is between 122 ppm and 220 ppm. As the lower bound of the interval is below 195, it is not reasonable to conclude that the mean magnesium ion concentration may be greater than 195

8 0

3 years ago