It is <span>Round 0.172 to the nearest hundredth.</span>
Answer:
The first one
Step-by-step explanation:
Mark me brainliest please
An= mth term.
an=a₁+(n-1)*d
a₁₂=41
a₁₅=140
a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d
a₁+11d=41 (1)
a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d
a₁+14d=140 (2)
With the equiations (1) and (2) build a system of equations
a₁+11d=41
a₁+14d=140
we solve it.
-(a₁+11d=41)
a₁+14d=140
--------------------
3d=99 ⇒d=99/3=33
a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322
an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n
an=-355+33n
To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
To solve this, we need to follow <em>PEMDAS </em>(Order of Operations)
P: Parenthesis
E: Exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction
Following this order of math will get you your answer for any math problem.
First we'll do -4*1/3, which gets us -4/3. Then we'll add 5 to get

<em>:)</em>
Answer: a) 2092278989 b) 576, c) 
Step-by-step explanation:
Since we have given that
Number of students = 16
Number of desks = 16
a) How many days must pass before the class must repeat a seating arrangement?

If the number of rows = 4
b) How many seating arrangements are there that put Larry, Moe, Curly, and Shemp in the front seats?

c) How many seating arrangements are there that put Larry, Moe, Curly, and Shemp in the front seats?

Hence, a) 2092278989 b) 576, c) 