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3 years ago

(2/5) Help me with this problem, please.

Mathematics

1 answer:

lana [24]3 years ago

4 0

You divided in the wrong order. The resulting image always goes first then the preimage is afterward.

scale factor = (new)/(old) = 10/8 = 1.25

<h3>Answer is choice B</h3>

The scale factor is larger than 1, so this means we have an enlargement going on.

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Decrease 620 by 10%

julia-pushkina [17]

Answer:

682

Step-by-step explanation:

620, percentage decreased by - 10% (percent) of its value = 682

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3 years ago

Do the equations y = -6x +4 and y = 4x + 6 have one solution, no solution, or infinitely many solutions

Black_prince [1.1K]

Answer:

One solution

Step-by-step explanation:

We know there is only one solution because the lines do not have the same slope, nor are they the exact same line.

So we know they must have just one solution.

Best of luck

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2 years ago

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25 POINTS & BRAINLIEST!<br><br> Is the following relation a function?<br><br> A. Yes<br> B. No

max2010maxim [7]

Answer:

A. Yes

Step-by-step explanation:

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3 years ago

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PLEASE HELP! <br> What percent of the circle is shaded? <br><br> Can you also explain to me please?

PolarNik [594]

Answer:

75%

Step-by-step explanation:

Look at it this way since there is 8 what u could do is 1/4 so 2 of them are 25% 4 of them are 50% 6 of them are 75% and all 8 are 100%

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3 years ago

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16. From past experience, a company has found that in cartons of transistors, 92% contain no defective transistors, 3% contain o

Lynna [10]

Answer:

E(x)=0.15

V(x)=0.3075

S(x)=0.5545

Step-by-step explanation:

The mean of a discrete variable is calculated as:

$E(x)=x_1*p(x_1)+x_2*p(x_2)+...+x_n*p(n)$

where $x_1,x_2,...,x_n$ are the values that the variable can take and $p(x_1),p(x_2),...,p(x_n)$ are their respective probabilities.

So, if we call x the number of defective transistors in cartons, we can calculate the mean E(x) as:

$E(x)=(0*0.92)+(1*0.03)+(2*0.03)+(3*0.02)=0.15$

Because there are 0 defective transistor with a probability of 0.92, 1 defective transistor with a probability of 0.03, 2 defective transistors with a probability of 0.03 and 3 defective transistors with a probability of 0.01.

At the same way, the variance V(x) is calculated as:

$V(x)=E(x^2)-(E(x))^2$

Where $E(x^2)=x_1^2*p(x_1)+x_2^2*p(x_2)+...+x_n^2*p(n)$

So, the variance V(x) is equal to:

$E(x^2)=(0^2*0.92)+(1^2*0.03)+(2^2*0.03)+(3^2*0.02)=0.33\\V(x)=0.33-(0.15)^2\\V(x)=0.3075$

Finally, the standard deviation is calculated as:

$S(x)=\sqrt{V(x)} \\S(x)=\sqrt{0.3075} \\S(x)=0.5545$

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3 years ago

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