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Scorpion4ik [409]

3 years ago

8

what is is 7 *10+ 7 i need to now please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

2 answers:

seraphim [82]3 years ago

8 0

Answer:

77

Step-by-step explanation:

7x10 is 70 plus 7 is 77

-Dominant- [34]3 years ago

3 0

7*10= 70+7=77

so ur answer is 77

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Answer:

-4.68

Step-by-step explanation:

i hope this helps

0.12 - 4.8 = -4.68

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Using long division to find the quotient, what changes do you first

lora16 [44]

Answer:

$\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4$

Step-by-step explanation:

Given

$Dividend = 125x^3 - 8$

$Divisor = 5x - 2$

Required

Determine the quotient

See attachment for complete process.

First, divide 125x^3 by 5x

$\frac{125x^3}{5x} =25x^2$

Write $25x^2$ at the top

Multiply $5x - 2$ by $25x^2$

$= 125x^3 - 50x^2$

Subtract from 125x^3 - 8

i.e.

$125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8$

Step 2:

Divide 50x^2 by 5x

$\frac{50x^2}{5x} = 10x$

Write $10x$ at the top

Multiply $5x - 2$ by $10x$

$= 50x^2 - 20x$

Subtract from 50x^2 - 8

i.e.

$50x^2 - 8 - (50x^2 - 20x) = 20x - 8$

Step 3:

Divide 20x by 5x

$\frac{20x}{5x} = 4$

Write $4$ at the top

Multiply $5x - 2$ by $4$

$= 20x - 8$

Subtract from 20x - 8

i.e.

$20x - 8 - (20x - 8) = 0$

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$\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4$

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3 years ago

0.5 to the second power x (20-2 to the third power x 3)x(2/5x25)

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Answer:

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Step-by-step explanation:

4 0

3 years ago

Jim was thinking of a number. Jim adds 20 to it, then doubles it and gets an answer of 99.2. What was the original number?

azamat

Alright, lets get started.

Jim was thinking of a number.

Suppose the number Jim was thinking, is x.

Jim adds 20 to it means number will be = $x+20$

And Jim doubles it, means $2*(x+20)$

Jim gets 99.2 and as per us, he gets $2*(x+20)$

So, making them equal

$2(x+20)=99.2$

$2x+40=99.2$

Subtracting 40 in both sides

$2x+40-40=99.2-40$

$2x=59.2$

$x=29.6$

It means the original number is 29.6. : Answer

Hope it will help :)

6 0

3 years ago