Ask question

Ask question

All categories

3 years ago

8

A line passes through the points (1, 4) and (3, –4). Which is the equation of the line?

1 answer:

Vikentia [17]3 years ago

5 0

Y = -4x + 8

First you need to find the slope of the line.

The slope formula is m = y2-y1/x2-x1

If you plugged in the points it would be m = -4-4/3-1

so m = -8/2 = -4

so the slope is -4

now we need to write the equation of the line

for this u use point slope form

the formula for that is y-y2=m(x-x1)

so if you plug it in it would be:

y-(-4)=-4(x-3)

now you solve

y+4=-4x+12

y+4-4= -4x+12-4

y = -4x + 8

and now you have the slope of the line

I hope this helps! :)

You might be interested in

Jocelyn and her children went into a bakery and she bought $9 worth of cookies and brownies. Each cookie costs $0.50 and each br

Yuliya22 [10]

Jace bought 4 cookies and 2 brownies from the bakery.

Let x represent the number of cookies and y represent the number of brownies.

Since he bought $9 worth of cookies and brownies. Each cookie costs $0.75 and each brownie costs $3. hence:

0.75x + 3y = 9 (1)

Also, he bought twice as many cookies as brownies, hence:

x = 2y

x - 2y = 0 (2)

Solving equation 1 and 2 simultaneously gives x = 4, y = 2

Hence Jace bought 4 cookies and 2 brownies from the bakery.

6 0

3 years ago

Using your answer from #3, how many hours will

Sphinxa [80]

Answer:

5 hours cuz 75 divided by 15 is 5 or 15 x 5 is 75

3 0

2 years ago

Read 2 more answers

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

HELP PLEASE! DELTA MATH! THANKS!

Eduardwww [97]

Answer:

11.5%

Step-by-step explanation:

hope this helps :))

5 0

3 years ago

Read 2 more answers

What multiple can you find 106

GrogVix [38]

106 times 1 to get 106

8 0

3 years ago

Read 2 more answers