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meriva
3 years ago
8

A line passes through the points (1, 4) and (3, –4). Which is the equation of the line?

Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
Y = -4x + 8

First you need to find the slope of the line.

The slope formula is m = y2-y1/x2-x1

If you plugged in the points it would be m = -4-4/3-1

so m = -8/2 = -4

so the slope is -4

now we need to write the equation of the line

for this u use point slope form

the formula for that is y-y2=m(x-x1)

so if you plug it in it would be:

y-(-4)=-4(x-3)

now you solve

y+4=-4x+12

y+4-4= -4x+12-4

y = -4x + 8

and now you have the slope of the line

I hope this helps! :)
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sweet-ann [11.9K]

Answer:

<u>Third Option</u>: y = \frac{5}{4}x

Step-by-step explanation:

Given the points on the graph, (4, 5) and (-4, -5):

In order to determine the equation of the given graph in slope-intercept form, y = mx + b:

Use the given points to solve for the slope:

Let (x₁, y₁) = (-4, -5)

(x₂, y₂) = (4, 5)

m = (y₂ - y₁)/(x₂ - x₁)

m = \frac{5 - (5)}{4 - (-4)}  = \frac{5 + 5}{4 + 4}  = \frac{10}{8} = \frac{5}{4}

Therefore, the slope of the line is: m = \frac{5}{4}.

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y = mx + b

5 = \frac{5}{4} (4) + b

5 = 5 + b

5 - 5 = 5 - 5 + b

0 = b

Therefore, the linear equation in slope-intercept form is: y = \frac{5}{4}x.  The correct answer is Option 3.

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