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kow [346]
3 years ago
11

Please tell me, how do i solve percentages? And yes, i know there is more than one way. Please tell me the methods to solve all

the ways. Like, how to do 45% of 20 or; 85 is 60% of __, or those questions that include stuff like taxes and other complicated things. I am in 6th grade and i am afraid i am about to fail, since i havent been turning in my Google Classroom assignments. Please help, will reward brainliest :(
Mathematics
1 answer:
Bumek [7]3 years ago
5 0
I'll give a practice problem to help explain it a bit better.

Here, let's try to solve 45% of of 60.

First, we convert the percentage into a decimal. To turn any percentage into a decimal you move the point two spaces to the left.

That means 45% as a decimal is .45.

Next, we multiply our number, 60, by the decimal .45.

60×.45=27.

That means 45% of 60 is 27.

To sum it all up, you have to get the percentage, move the decimal point two spaces to the left, and multiply it by the number you were trying to find the percentage of.

Have a wonderful day! :)
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Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
Maddie bought 3 2/3 yards of satin ribbon at the craft store. She wanted to make hair bows for the cheer squad. Each bow require
kotegsom [21]

Answer:

4

Step-by-step explanation:

Given that:

Total yards of satin bought by Maddie = 3\frac{2}{3} yards

Number of yards required make one ribbon = \frac{2}{3} yards

To find:

Number of complete bows that can be made ?

Solution:

First of all, let us learn about converting the mixed fraction to fractional form.

Formula:

a\dfrac{b}{c} = \dfrac{a\times c+b}{c}

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

3\dfrac{2}{3} = \dfrac{3\times 3+2}{3} = \dfrac{11}{3}

One hair bow requires \frac{2}{3} yards of ribbon.

Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.

Answer is:

\dfrac{\frac{11}{3}}{\frac{2}{3}}\\\Rightarrow \dfrac{11\times 3}{2\times 3}\\\approx 4

4 hair bows can be made.

4 0
2 years ago
Complete the following statement: f(3)=_____
victus00 [196]
Using this equation, f(3) = 23.

In order to find the value of f(3), we need to take the f(x) equation and put 3 everywhere we see x. Then we follow the order of operations to solve. So, let's start with the original. 

f(x) = 2x^2 + 5sqrt(x - 2) 

Now place 3 in for each x. 

f(3) = 2(3)^2 + 5sqrt(3 - 2)

Now square the 3.

f(3) = 2(9) + 5 sqrt(3 - 2)

Do the subtraction inside of the parenthesis. 

f(3) = 2(9) + 5sqrt(1)

Take the square root

f(3) = 2(9) + 5(1)

Multiply. 

f(3) = 18 + 5

And add. 

f(3) = 23

4 0
3 years ago
The height of a 12 year old boy increased by 17% last year and by 12% this year. What is the total increase in percent terms?
OverLord2011 [107]
He increased by 29% because you just add up the percentage 


3 0
3 years ago
Read 2 more answers
The table below shows some inputs and outputs of the invertible function f etc ​
Snowcat [4.5K]

Answer:

(a)\ f^{-1}(-15) = -6

(b)\ f^{-1}(4) + f(9)=0

Step-by-step explanation:

Given

The attached table

(a)\ f^{-1}(-15)

This represents an inverse function.

So, we look into x row for its value.

i.e.

f^{-1}(-15) = -6

(b)\ f^{-1}(4) + f(9)

Just like (a)

f^{-1}(4) = -11 ---- by looking into the x rows

f(9) = 11

So:

f^{-1}(4) + f(9)=-11 + 11

f^{-1}(4) + f(9)=0

4 0
2 years ago
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