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Zepler [3.9K]
3 years ago
10

How would you find the solutions to this quadratic equation y=2x^2-6x-8

Mathematics
2 answers:
aleksandrvk [35]3 years ago
8 0

Answer:

Factoring.

General Formulas and Concepts:

<u>Algebra I</u>

  • Factoring
  • Finding roots of quadratics

Step-by-step explanation:

<u>Step 1: Define</u>

y = 2x² - 6x - 8

0 = 2x² - 6x - 8

<u>Step 2: Find roots</u>

  1. Factor 2:                    0 = 2(x² - 3x - 4)
  2. Factor:                        0 = 2(x - 4)(x + 1)
  3. Find roots:                 x = -1, 4

And we have our final answer!

Marysya12 [62]3 years ago
7 0

Answer:

first take 2 out of the equation

y=2(x^2-3x-4)

then factor

y=2(x-4)(x+1)

then solve

(x-4)=0 .  (x+1)=0

x=4 .          x=-1

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