Question

How would you find the solutions to this quadratic equation y=2x^2-6x-8

Answer 1

Answer:

Factoring.

General Formulas and Concepts:

Algebra I

• Factoring
• Finding roots of quadratics

Step-by-step explanation:

Step 1: Define

y = 2x² - 6x - 8

0 = 2x² - 6x - 8

Step 2: Find roots

1. Factor 2:                    0 = 2(x² - 3x - 4)
2. Factor:                        0 = 2(x - 4)(x + 1)
3. Find roots:                 x = -1, 4

And we have our final answer!

Answer 2

Answer:

first take 2 out of the equation

y=2(x^2-3x-4)

then factor

y=2(x-4)(x+1)

then solve

(x-4)=0 .  (x+1)=0

x=4 .          x=-1