Question

Eliminate the parameter. x = t2 + 2, y = t2 - 4

Answer 1

$\bf \begin{cases} x=t^2+2\implies x-2=t^2\implies \sqrt{x-2}=\boxed{t}\\\\ y=t^2-4\\ ----------\\ y=\left( \boxed{\sqrt{x-2}} \right)^2-4\implies y=x-2-4\\\\ y=x-6 \end{cases}$

just a plain vanilla substitution

Answer 2

y = x-6 hope this helps