Question

Find g(-4) if g(x) = 8x^2 + 4x

Answer 1

Answer:

x = - 4

$g(x) = 8 {x}^{2} + 4x$

g(- 4) =?

$g( - 4) = 8( { - 4)}^{2} + 4( - 4) \\ g( - 4) = 8 \times 16 - 16 \\ g( - 4) = 128 - 16 \\ g( - 4) = 112$

=> g (- 4) = 112.

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