Question

A line passes through the point. (4, -7) and has a slope of 5/2

Answer 1

t p = through point

s = slope

$y - y(t \: p) = (s) \times ( \: x - x(t \: p) \: )$

$y - ( - 7) = \frac{5}{2} \times (x - 4)$

$y + 7 = \frac{5}{2} \times (x - 4)$

$y + 7 = \frac{5}{2}x - \frac{5 \times 4}{2}$

$y +7 = \frac{5}{2}x - \frac{20}{2}$

Subtract both sides -7

$y = \frac{5}{2}x - 10 - 7$

$y = \frac{5}{2}x - 17$

And we're done....

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