19 is a prime number so 1, 19
hope this helps!
Answer:
Is this the answer 95.2185
Answer: A
Step-by-step explanation:
A linear function is described as:
https://tex.z-dn.net/?f=f(x)%20%3D%20ax%20%2B%20b
When the value of x = 0, then you're left with
https://tex.z-dn.net/?f=f(x)%20%3D%20b
In this question, the speed of sound is the linear function while the temperature is the independent variable. When T = 0, you're left with
https://tex.z-dn.net/?f=S(0)%20%3D%20331.4
Which means the speed of sound in air when temperature is 0°C is 331.4m/s.
:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
