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3 years ago

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A person invests 10000 dollars in a bank. The bank pays 4.75% interest compounded semi-annually. To the nearest tenth of a year,

how long must the person leave the money in the bank until it reaches 19200 dollars?

1 answer:

hjlf3 years ago

8 0

Answer:

Step-by-step explanation:

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Choose the option with the proper number of sig figs

marishachu [46]

$\text{ 2 }\times10^8$

Explanation: $\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}$

let's break down the expression to get the final result:

$\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\ \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}$ $\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\ \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\ \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}$

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PLS HELP ME WITH MY MATH =3=<br>The sum of 10 and x is -12

Nezavi [6.7K]

Answer:

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Step-by-step explanation:

10 + x = -12

X = 12 - 10

X = 2

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