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SVEN [57.7K]
3 years ago
10

If the test scores in Personal Finance Unit 9 are normally distributed with a

Mathematics
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

68.269%

Step-by-step explanation:

We start by calculating the z-scores of both numbers

Mathematically;

z-score = (x-mean)/SD

where x represents the raw score

For 82;

z-score = (82-87)/5 = -5/5 = -1

For 92;

z-score = (92-87)/5 = 5/5 = 1

So the probability we want to calculate would be;

P(-1 < x< 1)

We can use the standard normal distribution table to get this.

By using the distribution, P(-1<x<1) = 0.68269

By converting this to percentage, we have 68.269%

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This relative frequency polygon shows pulse rates of women and men. Identity the midpoints of the class with the most pulse rate
Aleksandr-060686 [28]

Answer:

74.5 and 64.5

Step-by-step explanation:

Women midpoints:

54.5 - 0%

64.5 - 30%

74.5 - 35% (most pulse rates from women)

84.5 - 29%

94.5 - 2%

104.5 - 2%

114.5  - 0%

124.5 - 2%

Men midpoints:

0 - 0%

54.5 - 15%

64.5 - 43% (most pulse rates from men)

74.5 - 20%

84.5 - 20%

94.5 - 2%

104.5 - 0%

8 0
3 years ago
The scale of the map is missing. the actual distance from Liberty to West Quall is 72 miles, and it is 6 inches on the map.
podryga [215]
72:6

Scale: 72/6=12 --> 1: 12

4*12=foston from west quall 
48miles=foston from west quall

5 0
3 years ago
How do i factor 2y^2+y-10
Leokris [45]
2y^2+y-10
(2y+5)(y-2)
4 0
3 years ago
Read 2 more answers
5x - y + z = -6<br> 2x + 7y + 3z = 8<br> x + 2z = 6
BabaBlast [244]

Answer:

Step-by-step explanation:

The system of equations given are:

 

 5x - y + z = -6   ------------- i

 2x + 7y + 3z = 8  ---------- ii

  x + 2z = 6 ----------------- iii

Let us deal with equation i and ii first since they have 3 variables x, y and z;

      5x - y + z = -6                 x 7

       2x + 7y + 3z = 8            x 1

    35x  - 7y + 7z  = -42   ----  iv

      2x  + 7y + 3z  = 8       ---- v

Add equation iv and v;

    37x + 10z  = -34 ------vi

So, let us solve equation vi and iii:

               x + 2z = 6 - ---------- iii   x 10

               37x + 10z  = -34  --- iv  x 2

    10x + 20z   = 60         vi

     74x + 20z  = -68        vii

Subtract vi  - vii;

      -64x  = 128

          x  = -2

So;    put x  = -2 into iii;

           x + 2z  = 6

           -2 + 2z  = 6

            2z  = 6 + 2  = 8

           z  = 4

Put x  = -2 and z = 4 into equation i;

  5(-2) - y + 4  =  - 6

   -10 -y  +4  = -6

       -6  - y  = -6

             -y  = 0

              y  = 0

5 0
3 years ago
Can someone please help me with this; it's due tomorrow?
pochemuha
These aren't that hard--especially once you've done the first 13 questions. There are many 45-45-90 triangles in there.
  14. ∠BCO = 45°
  15. ∠GOF = 45°
  16. ∠OFG = 45°
  17. ∠GFH = 180° - ∠JFH = 58°
  18. ∠FGH = 90°
  19. ∠EFJ = 45°
  20. ∠GOC = 180° (the points are collinear)
6 0
3 years ago
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