Reminder: y = mx + b, to isolate y, you would need to subtract mx value, and what you do to one side, you do to all. If there’s a coefficient in front of your y value, you then divide the equation by that coefficient. Once y is isolated, m and b values are easier to find.
Answer:
1) y = -2x + 1 // m = -2, b = 1
2) y = 5/8x - 1 // m = 5/8, b = -1
3) y = 7/8x - 3/4 // m = 7/8, b = -3/4
4) y = 3/4x + 4 // m = 3/4, b = 4
The photographer just doubled the size of the 5 x 8 in photo
Area = length x width
24 = 3/4w
Divide both sides by 3/4
32 = w
The other side is 32 units
Answer:
The sum of all the numbers which are multiple of 5 between 5 an 1255 is 158,130
Step-by-step explanation:
In this question, we are asked to calculate the sum of all positive numbers that can be divided by 5 between 5 and 1255
To calculate this, we make use of the sum of an arithmetic progression
Mathematically, we have this as
Sn = n/2[a + L]
Where n is the number of terms which we do not know yet
a is the first term which is 5 and L is the last term which is 1255
Now to get n, we make use of the formula for finding the nth term of an arithmetic sequence
Tn = a+(n-1)d
where a is the first term which is 5 and d is the common difference which is also 5 with our Tn which is 1255
Substituting these values into the last term equation, we have
1255 = 5 + (n-1)5
1255 = 5 + 5n - 5
5n = 1255
n = 1255/5
n = 251
This means the number of terms we have in this arithmetic series is 251
Now we plug this n value into the sum equation
Thus,
Sn = 251/2(5 + 1255)
Sn = 251/2(1260)
Sn = 251 * 630
Sn = 158,130
Answer:
-2.35
Step-by-step explanation:
I'm not 100% Sure if that's correct but I'm pretty sure it is!