If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
<span>64-40ab
=8(8-5ab)
....................................</span>
Answer:
[three sixths] are the same amount as [one half]
Step-by-step explanation:
Call these units thirds. Split these units in half so there are twice as many. Call these units sixths because six of them make one.
Base times height, and then dives what you got by 2
