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ludmilkaskok [199]
3 years ago
12

Can u pls help me with this

Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

Problem 1:

x=12, x=3, x=6

Problem 2:

18*3=54

54/18=3

Problem 3:

Part A: 36/4.5=? 4.5*x=36

Part B: 8

Step-by-step explanation:

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In ΔPQR, m∠P = (3x+16) ,m∠Q=(4x-15),m∠R(2x+8) What is the value of x?
noname [10]

Answer:

  x = 19

Step-by-step explanation:

Assuming all angle measures are in degrees, the sum of them is 180:

  (3x +16) +(4x -15) +(2x +8) = 180

  9x +9 = 180 . . . . collect terms

  x + 1 = 20 . . . . . . divide by 9

  x = 19 . . . . . . . . . .subtract 1

The value of x is 19.

3 0
3 years ago
Can anyone pls help me in dis
Charra [1.4K]

Step-by-step explanation:

The coordinates of point A (2,8) and C (5,2)

The measure of segment AC

\sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2}  }

\sqrt{ {(5 - 2)}^{2}  +  {(2 - 8)}^{2} }

\sqrt{ {(3)}^{2} +  {( - 6)}^{2}  }

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6.7 \: units

8 0
3 years ago
Help Me with this question please​
artcher [175]

Answer:

22

Step-by-step explanation:

The abs of y is 29 because 29 is positive

51 - 29 = 22

4 0
3 years ago
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Under the best conditions, a sprout has a 40% probability of blooming.if two sprouts are selected at random, what is the probabi
Minchanka [31]
The answer is 16 % :D 
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3 years ago
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2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
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