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vovangra [49]
3 years ago
15

Write code which takes a user input of a String and an integer. The code should print each letter of the String the number of ti

mes the user inputted in reverse order.
Sample run:

Input a String:
code
Input an integer:
3
eeedddoooccc


Note: Write In Java
Thank You...
Computers and Technology
2 answers:
Alexus [3.1K]3 years ago
7 0

import java.util.Scanner;

public class JavaApplication70 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Input a String:");

       String txt = scan.nextLine();

       System.out.println("Input an integer:");

       int num = scan.nextInt();

       String newTxt = "";

       int w = 0;

       for (int i = txt.length()-1; i >= 0; i--){

           char c = txt.charAt(i);

           while (w < num){

               newTxt += c;

               w++;

           }

           w = 0;

       }

       System.out.println(newTxt);

   }

   

}

I hope this helps!

Nesterboy [21]3 years ago
6 0

Answer:

import java.util.*;  

class Main {  

 public static void main(String args[]) {

   Scanner sc= new Scanner(System.in);

   

   System.out.print("Input a String: ");  

   String str = sc.nextLine();  

   

   System.out.print("Input an integer: ");  

   int num = sc.nextInt();  

   

   for(int i=str.length()-1; i>=0; i--) {

       for(int j=0; j<num; j++) {

           System.out.print(str.charAt(i));

       }

   }

         

 }

}

Explanation:

There you go.

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Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th
ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0
3 years ago
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