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MariettaO [177]

2 years ago

8

miguel is posting photos on school website hi has 48 photos and he followed 12 pages he whant to put the same number put of phot

os ,p, on each page

2 answers:

Serjik [45]2 years ago

8 0

Answer:

12p = 48

Step-by-step explanation:

We already know Miguel has 48 photos already selected, with 12 pages to chose from. Since we want to figure out an equation for the number of photos Miguel is going to put on each page, you would have to do this: we do know the number of pages Miguel has but we don't know how many photos per page. So, you would write 12p for the unknown number of photos per page. Since he already has 48 photos and the 48 will not be affected during this equation, the answer to the equation would equal 48. So, the final answer would be 12p = 48

Ksivusya [100]2 years ago

4 0

Answer:

4

Step-by-step explanation:

48/12=4

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If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

Last weekend, Carlos rode his bicycle for 3 hours and traveled 27 miles. On average, at what rate did Carlos travel on his bicyc

mash [69]

Carlos rode an average of 9 miles every hour on his bicycle. It is because 3*9=27 and the distance is rate multiplied by time. use the formula and check it!

Hope I helped.

Good Luck!

5 0

3 years ago

What does 5 3/4+7 1/2 equal

Natalija [7]

Answer:

5 3/4+7 1/2

5.75 + 7.50 = 13.25 or 13 1/4

Step-by-step explanation:

5 3/4+7 1/2

5.75 + 7.50 = 13.25 or 13 1/4

4 0

2 years ago

Formulas A=bh/2 A=bh and I have 6in 4in 6in 10in and I have to find the area

Naddik [55]

Answer:

Lots of "ifs" here.

A=bh/2 is the formula for the area of a triangle.

A=bh is the formula for the area of a rectangle or a parallelogram.

If the 6 & 4 area the base & height of a rectangle, then (6)(4) = 24 in^2

If the 6 & 10 are the base and height of a triangle, then 1/2(6)(10) = 30 in^2

Step-by-step explanation:

6 0

3 years ago

A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe

Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

$\omega=\frac{v}{r}$ ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

$47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}$

next, you replace the values of v and r in the equation (1):

$\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}$

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

8 0

2 years ago