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PSYCHO15rus [73]
3 years ago
14

What is the value of x?

Mathematics
1 answer:
Lelechka [254]3 years ago
5 0
X = 35

use the formula a^2 + b^2 = c^2 in order to find the hypotenuse, which is x.

21^2 + 28^2 = c^2
441 + 784 = c^2
1225 = c^2
35 = c

x = 35
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-p+78x+39

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What is the relation between real number and whole number
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The set of real numbers is all numbers that can be shown on a number line. It also includes rational numbers, which are numbers that can be written as a ratio of two integers, and irrational numbers, which cannot be written as a the ratio of two integers.
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A bag has 3 red marbles, 3 blue, 4 green and 2 yellow. What is the theoretical probability of pulling a red marble?
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Answer:

Fraction: \frac{1}{4}

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Step-by-step explanation:

Have a good day :)

4 0
3 years ago
The city has an average of 13 days of rainfall for April.
zhenek [66]

Using the Poisson distribution, we have that:

  • There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.
  • There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.
  • There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

For this problem, the mean is given as follows:

\mu = 13

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0

P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003

P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0
1 year ago
Justify the last two steps of the proof.
Georgia [21]
Statement 3:

NO and ON are the same line. They are congruent by the reflexive property (a line segment is a reflection of itself).

Statement 4:

Shape MNO and shape PON are congruent by side-side-side since:

side PN = side MO
side MN = side PO
side NO = side ON

Answer: Fourth option
3 0
3 years ago
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