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3 years ago

3. El grupo de Mariana se organizó en seis equipos. Cada equi-

Mathematics

1 answer:

MakcuM [25]3 years ago

3 0

Answer:

¿en qué periodos le tocará participar?

El equipo cuatro participa en el periodo 5 - 11 - 17

¿Todos los equipos participarán el mismo número de veces?

Todos los equipos los hacen 3 veces . menos 1 equipo que lo hace 2 veces

¿Por qué?

Cuatrimestre. = 120 dias

Numero de semanas = 120/ 7 17,1

17 semanas completas 3 dias

No se trabaja la primera semana. por lo que quedan 16 semana 3 dias.

Son 6 equipos para participar todos serian por lo menos 17 semanas 1 dia.

Step-by-step explanation:

Cuatrimestre. = 120 dias

Numero de semanas = 120/ 7 17,1

17 semanas completas 3 dias

No se trabaja la primera semana. por lo que quedan 16 semana 3 dias.

Son seis equipos. 17 ( 16,3) semanas / 6

Todos los equipos los hacen 3 veces . menos 1 equipo que lo hace 2 veces

Semana 1 2 3 4 5 6

Equipos

2 X

3 X

4 X

5 X

6 X

7 X

8 X

9 X

10 X

11 X

12 X

13 X

14 X

15 X

16 X

17 X

18 X

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vekshin1

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

The graph of f(x) = (0.5)x is replaced by the graph of g(x) = (0.5)x − k. If g(x) is obtained by shifting f(x) down by 7 units,

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3 years ago

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An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile the width of the lake is 1/5 the length of

DIA [1.3K]

Answer: The dimensions are:   " 1.5 mi.  × ³⁄₁₀ mi. " .
_______________________________________________
{ length = 1.5 mi. ; width = ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ;

in which: A = Area = (9/20) mi.² ,
L = Length = ?
w = width = (1/5)*L = (L/5) = ?
________________________________________
A = L * w ; we want to find the dimensions; that is, the values for
"Length (L)" and "width (w)" ;
_______________________________________
Plug in our given values:
_______________________________________
(9/20) mi.² = L * (L/5) ; in which: "w = L/5" ;

→ (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;

   ↔ L² / 5 = 9/20 ;

  → (L² * ? / 5 * ?) = 9/20 ?

→ 20÷5 = 4 ; so; L² *4 = 9 ;

    ↔ 4 L² = 9 ;

→ Divide EACH side of the equation by "4" ;

→ (4 L²) / 4 = 9/4 ;
______________________________________
to get: → L² = 9/4 ;
Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
___________________________________________

→   ⁺√(L²) = ⁺√(9/4) ;

→   L = (√9) / (√4) ;

→ L = 3/2 ;

→ w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
________________________________________________________
Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

→ (3/2)mi. * (3/10)mi. = (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
______________________________________________________
So the dimensions are:

Length = (3/2) mi. ; write as: 1.5 mi.

width = ³⁄₁₀ mi.
___________________________________________________
or; write as: " 1.5 mi. × ³⁄₁₀ mi. " .
___________________________________________________

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