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antoniya [11.8K]
3 years ago
10

(HELP ASAP)In the figure, if OQ is the angle bisector of ∠POR, find m∠POQ.

Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Answer:

61°

Step-by-step explanation:

9x+7=13x-17, QO Bisector

x=6\\, Algebra

m, Algebra/Sub

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34k+(6.3−8.1k)÷0.9=22
KATRIN_1 [288]

We have been given an equation 34k+(6.3-8.1k)\div 0.9=22. We are supposed to solve our given equation for k.

We can rewrite our given equation as:

34k+\frac{6.3-8.1k}{0.9}=22

Let us multiply both sides of equation by 0.9.

34k\cdot 0.9+\frac{6.3-8.1k}{0.9}\cdot 0.9=22\cdot 0.9

30.6k+6.3-8.1k=19.8

22.5k+6.3=19.8

22.5k+6.3-6.3=19.8-6.3

22.5k=13.5

\frac{22.5k}{22.5}=\frac{13.5}{22.5}

k=0.6

Therefore, the value of the k is 0.6.

8 0
3 years ago
What is the slope of a line parallel to the line whose equation is 3x−2y=18. Fully reduce your answer.
choli [55]

Answer:

3/2x

Step-by-step explanation:

-2y = -3x+18

y = 3/2x-9

7 0
3 years ago
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A toy rocket is launched from a platform that is 48 ft high. The rocket height above the ground is modeled by h=-16t^2+32t+48. a
Komok [63]

Answer:

a) 64 feet

b)  3 seconds

Step-by-step explanation:

a)

The maximum height of h=h(t) can be bound by finding the y-coordinate of the vertex of y=-16x^2+32x+48.

Compare this equation to y=ax^2+bx+c to find the values of a,b,\text{ and } c.

a=-16

b=32

c=48.

The x-coordinate of the vertex can be found by evaluating:

\frac{-b}{2a}=\frac{-32}{2(-16)

\frac{-b}{2a}=\frac{-32}{-32}

\frac{-b}{2a}=1

So the x-coordinate of the vertex is 1.

The y-coordinate can be found be evaluating y=-16x^2+32x+48 at x=1:

y=-16(1)^2+32(1)+48

y=-16+32+48

y=16+48

y=64

So the maximum height of the rocket is 64 ft high.

b)

When the rocket hit's the ground the height that the rocket will be from the ground is 0 ft.

So we are trying to find the second t such that:

0=-16t^2+32t+48

I'm going to divide both sides by -16:

0=t^2-2t-3

Now we need to find two numbers that multiply to be -3 and add to be -2.

Those numbers are -3 and 1 since (-3)(1)=-3 and (-3)+(1)=-2.

0=(t-3)(t+1)

This implies we have either t-3=0 or t+1=0

The first equation can be solved by adding 3 on both sides: t=3.

The second equation can be solved by subtracting 1 on both sides: t=-1.

So when t=3 seconds, is when the rocket has hit the ground.

5 0
3 years ago
What is the reciprocal of 0.125
lesya692 [45]
1/0.125
I really hope this helps
6 0
3 years ago
Can anyone help me ASAP!
TiliK225 [7]

Answer:

17.3 in

Step-by-step explanation:

5 0
3 years ago
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