Answer:
A 99% confidence interval will be wider than a 95% confidence interval
Step-by-step explanation:
From the question we are told that
The 95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm
Generally the width of a confidence interval is dependent on the margin of error.
Generally the margin of error is mathematically represented as
From the above equation we see that
Here 
is the critical value of the half of the level of significance and this value increase as the confidence level increase
Now if a 99% confidence level is used , it then means that the value of
will increase, this in turn will increase the margin of error and in turn this will increase the width of the confidence interval
Hence a 99% confidence interval will be wider than a 95% confidence interval
Answer:
72°
Step-by-step explanation:
Given
Zy = 108°
Zx = ?
We know
Zx + Zy = 180° {being supplementary angles }
Zx + 108° = 180°
Zx = 180° - 108°
Zx = 72°
Hope it will help :)
$2,620
$0,750
$0,630
$0,050
$0,090
+$0,425
=$4,665
Answer:
See below.
Step-by-step explanation:
Here's an example to illustrate the method:
f(x) = 3x^2 - 6x + 10
First divide the first 2 terms by the coefficient of x^2 , which is 3:
= 3(x^2 - 2x) + 10
Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form
(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.
= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)
= 3 [(x - 1)^2 -1 ] + 10
= 3(x - 1)^2 - 3 + 10
= <u>3(x - 1)^2 + 7 </u><------- Vertex form.
In general form the vertex form of:
ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .
This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.
