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Alex73 [517]
3 years ago
6

Find the average rate of change of f(x) = 4x² – 3 from 3 to 9.

Mathematics
1 answer:
Lina20 [59]3 years ago
3 0

Answer:

44

Step-by-step explanation:

Given:

f(x) = 4x^2 - 3

Required:

Average range of change from 3 to 9

SOLUTION:

Step 1:

Find f(3) and f(9):

To find f(3), replace x with 3 in the given function

f(3) = 4(3)^2 - 3

f(3) = 4(9) - 3

f(3) = 36 - 3

f(3) = 33

To find f(9), replace x with 9 in the given function

f(9) = 4(9)^2 - 3

f(9) = 4(81) - 3

f(9) = 324 - 3

f(9) = 321

Average rate of change = \frac{f(b) - f(a)}{b - a}

Where,

a = 3, f(a) = 33

b = 9, f(b) = 321

Plug in the values into the formula for average rate of change.

= \frac{321 - 33}{9 - 3}

= \frac{288}{6}

= 44

Average rate of change = 44

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Answer:

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Step-by-step explanation:

The area of a circle is given by the formula

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We know the area  = 78.5 in^2   (volume would be in^3   area is in^2)

78.5 = 3.14*r^2

Divide each side by 3.14

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Answer:

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Exp Time: 4:00am

Prep Date: 12/3/2016

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Initials: 12/7/2016

Step-by-step explanation:

A well-detailed version of the question has been uploaded in form of an image for easier understand.

Looking at the question, it was said that she received her store order on 12/3/2016 at 4am, this implies that the prep date and time are 12/3/2016 and 4am respectively. Also, it was said that the expiration date was printed on the product and it is 1/17/2017. Obviously, the expiration time would also be 4am because it was prepared at 4am and if we calculate in. 24hours we would get 4am at the expiration date as well. Lastly, we were told she opened the product she received on 12/7/2016 which is the initial date the product was used. From all these we can deduce the following:

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Prep Date: 12/3/2016

Prep Time: 4:00am

Initials: 12/7/2016

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