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rewona [7]
2 years ago
8

((6x^4 y^5 z^(-2))/(3xy^3 ))^2

Mathematics
1 answer:
Marina86 [1]2 years ago
4 0

Answer:

4x^6 y^4 / z^4

Step-by-step explanation:

you have to divide each of the variables by the coefficient

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Where is the exact volume of the sphere
baherus [9]

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12.3 \end{cases}\implies V=\cfrac{4\pi (12.3)^3}{3}\implies \stackrel{\pi =3.14}{V\approx 7790.83}

7 0
3 years ago
The temperature of a city is recorded at midnight on the last days of four consecutive months
Serhud [2]

Answer:

26 degrees Celcius

Step-by-step explanation:

The minimum temperature is -11

The maximum temperature is 15

to get from -11 to 0: add 11

to get from 0 to 15: add 15

11+15 = 26

6 0
2 years ago
Rewrite the expression in the form z^n
olga55 [171]

Answer:

{z}^{ \frac{1}{2} }

Step-by-step explanation:

\huge \sqrt[5]{ {z}^{4} {z}^{ -  \frac{3}{2} }  }  \\  \\  =  \huge \sqrt[5]{ {z}^{4 -  \frac{3}{2}  }  } \\  \\  =  \huge \sqrt[5]{ {z}^{ \frac{8 - 3}{2}  }  } \\  \\  =  \huge \sqrt[5]{ {z}^{ \frac{5}{2}  }  }  \\  \\  = \huge   {z}^{ \frac{5}{2}  \times  \frac{1}{5} }  \\  \\ = \huge   {z}^{ \frac{1}{2} }

3 0
3 years ago
Find 6 rational numbers between 8 and 9​
Lena [83]

Answer:

Step-by-step explanation:

8,1                              8,2

8,3                            8,4          

8,5                            8,6

4 0
3 years ago
At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
2 years ago
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