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abruzzese [7]
4 years ago
6

We want to place a bench measuring 7.05 feet in the center of a platform that is 40.75 feet long. What is the distance from each

side of the bench to the edges of the platform
Mathematics
1 answer:
alexandr402 [8]4 years ago
6 0

Answer:  The distance from each side of the bench to the edges of the platform = 16.85 feet.

Explanation:

Length of platform = 40.75 feet

Length of bench  = 7.05 feet

Let the distance from each side of the bench to the edges of the platform be x

So, it becomes x+7.05+x = 40.75

⇒2x+7.05= 40.75

⇒2x = 40.75- 7.05

⇒x = 33.7

⇒x=\frac{33.7}{2}

⇒x= 16.85 feet .

So, the distance from each side of the bench to the edges of the platform = 16.85 feet.

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Paul [167]

Answer:

113.7-2.154\frac{9.1}{\sqrt{29}}=110.06    

113.7+2.154\frac{9.1}{\sqrt{29}}=117.34    

And the 96% confidence is given by (110.06; 117.34)

Step-by-step explanation:

Information given

\bar X=113.7 represent the sample mean

\mu population mean (variable of interest)

s=9.1 represent the sample standard deviation

n=29 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=29-1=28

The Confidence is 0.96 or 96%, the significance is \alpha=0.04 and \alpha/2 =0.02, and the critical value would be t_{\alpha/2}=2.154

Replacing the info we got:

113.7-2.154\frac{9.1}{\sqrt{29}}=110.06    

113.7+2.154\frac{9.1}{\sqrt{29}}=117.34    

And the 96% confidence is given by (110.06; 117.34)

5 0
4 years ago
Help? (only people who know what they're doing please)
Temka [501]
X would equal 2.7 //////////////
7 0
3 years ago
a rectangle shape whose length is 4 inches less than twice its width. the area is 30 square inches. whats the dimension
Ne4ueva [31]
Using the given information, we can say the following:
Width (W) = x
Length (L) = (2x - 4)
Area of Rectangle = L × W
Using this, we can formulate an equation for rectangle in question:
x(2x - 4) = 30
Expand and move everything to one side:
2x² - 4x - 30 = 0
Simplify by dividing everything on both sides by 2:
x² - 2x - 15 = 0
Factorise:
(x + 5)(x - 3) = 0
Set each factor equal to 0 and solve for x:
x + 5 = 0
x = -5 (a dimension cannot be negative so this is not the solution we want)
x - 3 = 0
x = 3 (this is the solution)
x = W = 3"
L = 2x - 4
L = 2(3) - 4
L = 2"

So, the length the rectangle is 2" and the width is 3"
5 0
4 years ago
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