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abruzzese [7]
3 years ago
6

We want to place a bench measuring 7.05 feet in the center of a platform that is 40.75 feet long. What is the distance from each

side of the bench to the edges of the platform
Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:  The distance from each side of the bench to the edges of the platform = 16.85 feet.

Explanation:

Length of platform = 40.75 feet

Length of bench  = 7.05 feet

Let the distance from each side of the bench to the edges of the platform be x

So, it becomes x+7.05+x = 40.75

⇒2x+7.05= 40.75

⇒2x = 40.75- 7.05

⇒x = 33.7

⇒x=\frac{33.7}{2}

⇒x= 16.85 feet .

So, the distance from each side of the bench to the edges of the platform = 16.85 feet.

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Answer:

A: Exponential

B: Quadratic

C: Linear

Step-by-step explanation:

Let analyse each table

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X            Y              ΔY/ΔX

1             5               xxxxxx              

2            11            11 - 5 = 6            

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4           83             83 - 29 = 54

.....................

We can see that, [ ΔY/ΔX ]   increases at the fastest rate out of all functions, so it must be exponential function

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X            Y                 ΔY/ΔX            Δ^2Y/ΔX^2          

0             5                 xxxxxx              xxx              

1              7                 7 - 5 = 2            xxx            

2             13               13 - 7 = 6           6-2 = 4        

3             23              23 - 13 = 10       10-6 = 4

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It is a quadratic because Δ^2Y/ΔX^2 = 4 and are constant for all values

  • Table C

X            Y                 ΔY/ΔX                      

3             20               xxxxxx                  

6             18                 2 / 3

9             16                 2 / 3                    

15            12                 2 / 3      

..............

It is a linear because ΔY/ΔX = 2/3 are constant for all values

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8090 [49]
Given 
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Solution
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-----    ---------    ---->     y   = -------    ----------->  y= 5
 6           6                              6

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