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lara [203]
3 years ago
8

If 18 percent of the beads in a bag are green, 25 percent are red and 40 percent are purple. What is the probablity of choosing

a green bead then a red bead
Mathematics
1 answer:
sweet [91]3 years ago
7 0

Answer:

P(G\ then\ R)=0.045

Step-by-step explanation:

From the question we are told that:

Percentage of  Green beads P_g=18

Percentage of  Red beads    P_r=18

Percentage of Purple beads P_p=18

Therefore

Probability of choosing a Green bead is

 P(G)=0.18

Probability of choosing a Red bead is

 P(R)=0.25

Generally the equation for choosing a green bead then a red bead is mathematically given by

Since Outcomes are independent

 P(G\ then\ R)=0.18*0.25

 P(G\ then\ R)=0.045

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Answer:

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Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

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So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

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So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

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Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

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