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Dafna1 [17]
3 years ago
9

I NEED HELP ON A TEST HELP QUICK

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0
Boats are blue and red
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Factor the expression below. Pls help!
amm1812
I think this is right (x-2)(2x+y) 
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frosja888 [35]
B. D=0.25n + 25
D=total n=number of hours 0.25=price per hour 25=the one time fee
3 0
3 years ago
You are making a lot of cookies and buy 12 bags of chocolate chips, which are $1.89 per bag
Liono4ka [1.6K]

Answer:

$22.68

Step-by-step explanation:

5 0
3 years ago
Just runs 11 miles in 67 minutes how many miles does he run per minute<br>​
alina1380 [7]

Answer

Just runs 7 minutes per mile

Step by Step explanation

Divide 11 by both numbers which leaves you with

1/6

Because you have to divide 11 by 11 and 67 by 11

when you calculate it you get 6.090909091

so you can round it to 7.

8 0
3 years ago
2.A production process manufactures items with weights that are normally distributed with mean 10 pounds and standard deviation
Vesna [10]

Answer:

Step-by-step explanation:

Given that:

population mean = 10

standard deviation = 0.1

sample mean = 9.8 < x > 10.2

The z score can be computed as:

z = \dfrac{\bar x - \mu}{\sigma}

if x > 10.2

z = \dfrac{10.2- 10}{0.1}

z = \dfrac{0.2}{0.1}

z = 2

If x < 9.8

z = \dfrac{9.8- 10}{0.1}

z = \dfrac{-0.2}{0.1}

z = -2

The p-value = P (z ≤ 2) + P (z ≥ 2)

The p-value = P (z ≤ 2) + ( 1 -  P (z ≥ 2)

p-value = 0.022750 +(1 -   0.97725)

p-value = 0.022750 +  0.022750

p-value = 0.0455

Therefore; the probability of defectives  = 4.55%

the probability of acceptable = 1 - the probability of defectives

the probability of acceptable = 1 - 0.0455

the probability of acceptable = 0.9545

the probability of acceptable = 95.45%

4.55% are defective or 95.45% is acceptable.

sampling distribution of proportions:

sample size n=1000

p = 0.0455

The z - score for this distribution at most 5% of the items is;

z = \dfrac{0.05 - 0.0455}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{0.0045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = \dfrac{0.0045}{\sqrt{4.342975 \times 10^{-5}}}

z = 0.6828

The p-value = P(z ≤ 0.6828)

From the z tables

p-value = 0.7526

Thus, the probability that at most 5% of the items in a given batch will be defective = 0.7526

The z - score for this distribution for at least 85% of the items is;

z = \dfrac{0.85 - 0.9545}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{-0.1045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = −15.86

p-value = P(z ≥  -15.86)

p-value = 1 - P(z <  -15.86)

p-value = 1 - 0

p-value = 1

Thus, the probability that at least 85% of these items in a given batch will be acceptable = 1

6 0
3 years ago
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