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pashok25 [27]
3 years ago
5

Just 7 i really dont want to do the work 3

Mathematics
1 answer:
leonid [27]3 years ago
3 0

Answer:

267

Step-by-step explanation:

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One hose can fill a small swimming pool in 90 minutes. A larger hose can fill the pool in 30 minutes. How long will it take the
Vesnalui [34]

Working together they would fill two pools in 120 minutes so therefore they would fill one pool in 60 minutes

8 0
3 years ago
Read 2 more answers
the equation of line s is y=-x+7. line t is perpendicular to line s and passes through (-3,2). What is the equation of line t?
Leto [7]

Answer:

y=x-5

Step-by-step explanation:

slope of line s=-1= m1

lines are perpendicular m1m2=-1 m2=1

equations of t=y-y1=m2(x-x1)

y-2=x+3

y=x+5

6 0
3 years ago
On a weekend trip around California, Sydney left her home in Modesto and drive 75 miles east to Yosemite National Park, then 70
alekssr [168]
75 mi. East, 70 mi. South, 110 mi.West.
Overall, she drove 110-75= 35 mi. West since east & west are opposite directions.
And 70 mi. South.
In a Pythagorean theorem problem, legs are 35 & 70. And hypotenuse is her diagonal distance from where she started
35^2 + 70^2 = c^2
1225 + 4900 = c^2
6125 = c^2
78.3=c
6 0
4 years ago
Please help me with this question.
Reil [10]

Answer:

13.5 m/s

Step-by-step explanation:

To start off, simply plug in the values into the equation. This is shown below...

<u>v = velocity</u>

<u>u = initial velocity</u>

<u>a = acceleration</u>

<u>t = time</u>

v = u + at    --->    v = 3 + 1.5(7)

First, multiply 1.5 and 7 together. By doing so, you get 10.5. Now the equation is...

v = 3 + 10.5

To finish, simply add 3 and 10.5...

v = 3 + 10.5    --->    v = 13.5

<u>Your answer is 13.5 m/s</u>

4 0
4 years ago
Solve the ODE y'+xy=x² with y(0)=2​
goldenfox [79]
If you take the derivative of your equation, you get:

2′″−″−′+′=0
2
y
′
y
″
−
x
y
″
−
y
′
+
y
′
=
0

or

″(2′−)=0.
y
″
(
2
y
′
−
x
)
=
0.

Let =′
v
=
y
′
and we have ′(2−)=0,
v
′
(
2
v
−
x
)
=
0
,
so either ′=0
v
′
=
0
and =
v
=
c
or =/2
v
=
x
/
2
.

Then ′=
y
′
=
c
and so =+
y
=
c
x
+
d
or ′=/2
y
′
=
x
/
2
and =2/4.
y
=
x
2
/
4.

Plugging the first into the original equation gives =−2
d
=
−
c
2
. So there are two solutions =−2
y
=
c
x
−
c
2
for some constant
c
and =2/4
y
=
x
2
/
4
. I don't know if this is all the solutions
7 0
3 years ago
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