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3 years ago

Plss answer i will give brainliest

Mathematics

2 answers:

Kobotan [32]3 years ago

8 0

Answer:

10 desserts

Step-by-step explanation:

For this question, in order to find all the combinations of desserts, you need to multiply the sizes, flavors, and toppings together.

See:

$Sizes * Flavors * Toppings = 2 * 1 * 5 = 10$

10 desserts

Mnenie [13.5K]3 years ago

5 0

Answer:

Step-by-step explanation:

(1 + 1 + 1) x 5 = 5

this is tooo easy.

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Help with this question please!!

kkurt [141]

Answer:

The second one, 160

Step-by-step explanation:

3+3+5+8=19, and 380/19=20 so each unit is 20cm

8 is the largest side --> 8*20 = 160

3 0

3 years ago

Please help I will give brainliest if its correct :) Question is in picture

Nonamiya [84]

Answer:

2.5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

the london eye, a ferris wheel in England, has a diameter of 120 meters. This wheel completes a full rotation in 30 minutes at a

hram777 [196]

Given in the problem is the diameter of the Ferris Wheel.

Thus, we can compute for the Ferris Wheel Circumference. This is the circular distance a single capsule attached to the wheel needs to do a full circle to.

Using 2 Step, we find the rate of how fast the capsule needs to be moving to complete 1 full cycle in 30 minutes.
1. Formula for computing the circumference
C = 2 x π x R

where R = Diameter divided by 2

C = 2π(120/2 )
C = 120π

2. Compute the rate or speed of the capsule / coach.
Rate or Speed = Distance to cover / Time it takes to cover
R/S = 120π/30 = 4π m/min or 12.57737 meters / min

4 0

4 years ago

How to solve this trig

n200080 [17]

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

$\displaystyle \large{ cos \theta = - \frac{1}{2} }$

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

$\displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }$

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }$

Both values are apart of the interval. Hence,

$\displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }$

Second Question

Isolate sin(4 theta).

$\displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }$

Rationalize the denominator.

$\displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }$

The problem here is 4 beside theta. What we are going to do is to expand the interval.

$\displaystyle \large{0 \leqslant \theta < 2 \pi}$

Multiply whole by 4.

$\displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}$

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }$

Find Q4

$\displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }$

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

$\displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}$

Hence:-

For Q3

$\displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }$

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

$\displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }$

Therefore:-

$\displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }$

Then we divide all these values by 4.

$\displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }$

Let me know if you have any questions!

3 0

3 years ago

Compare 0.55 ____ 0.525 using , or =

fredd [130]

Answer:

0.55 > 0.525

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers