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blagie [28]
3 years ago
6

Plss answer i will give brainliest

Mathematics
2 answers:
Kobotan [32]3 years ago
8 0

Answer:

10 desserts

Step-by-step explanation:

For this question, in order to find all the combinations of desserts, you need to multiply the sizes, flavors, and toppings together.

See:

Sizes * Flavors * Toppings = 2 * 1 * 5 = 10

10 desserts

Mnenie [13.5K]3 years ago
5 0

Answer:

10

Step-by-step explanation:

(1 + 1 + 1) x 5 = 5

(1 + 1 + 1) x 5 = 5

this is tooo easy.

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Mom is 8 years older than 4 times Sarah’s age. The sum of their ages is less than 83. What is Sarah’s oldest possible age?
tigry1 [53]

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3 0
3 years ago
X2 + 8x + 19 = 0 What is the equivilent that results from completing the square?
IrinaVladis [17]

Answer:

(x+4)^2+3=0

Step-by-step explanation:

Hey there!

Standard form is what this equation is in

Standard form is this: ax^2+bx+c

So order to complete the square, you need to take the b term out of the equation, divide it by two, and then square it

In this case, the b term is 8

We need to divide 8 by 2 ---> 4

Then square 4 ---> 16

So now you should add 16 to both sides

x^2+8x+16+19=16

Now you can simplify the LHS

(x+4)^2 +19=16

Now you subtract 16 from both sides

(x+4)^2+3=0

So this is as far as you can go since you cannot take the square root of a negative number

5 0
2 years ago
Find an equation in standard form for the hyperbola with vertices at (0,plus or minus 6) and asymptotes at y= (plus or minus 3/5
antoniya [11.8K]

Answer:

\frac{(y)^2}{36}-\frac{(x)^2}{100}=1

Step-by-step explanation:

Given:

Vertices of Hyperbola : (0 ± 6) or (0,6) and (0,-6)

and asymptotes at y= (±3/5)x 0r y= 3/5 x and y=-3/5 x

The vertices are of vertical hyperbola. The equation used will be:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\\

The Center of hyperbola (h,k) =(0,0)

The Distance from vertices to center is a and a = 6 (given)

For equation we have value of h,k and a and need to find value of b

we know,

y= k ± a/b (x-h)

Values of h and k are zero

y= 0 ± a/b (x-0)

y= (± a/b ) x

We are given asymtotes at y= (± 3/5)x which is equal to y= (± a/b ) x

as a = 6 then b= 10 i.e The simplified form of 6/10 is 3/5 so value of b=10

Putting values of a,b,h and k in equation we get,

\frac{(y-0)^2}{(6)^2}-\frac{(x-0)^2}{(10)^2}=1\\\\\frac{(y)^2}{36}-\frac{(x)^2}{100}=1

7 0
4 years ago
The length of a rectangle is 10 inches longer than its width. If the area of the rectangle is 144 square inches, what are its di
vazorg [7]

Answer:

L= 18 in

W= 8 in

Step-by-step explanation:

Step one:

The length of a rectangle is 10 inches longer than its width

let the width be x

so the lenght is x+10

the area of the rectangle is 144 square inches

Step two:

Area= L*W\\\\144=x(x+10)\\\\144=x^2+10x\\\\x^2+10x-144=0

the factors for the quadratic expression is

18 and -8

x^2+18x-8x-144=0\\\\x(x+18)-8(x+18)=0\\\\x-8=0\\\\x=8\\\\x+18=0\\\\x=-18

the width is 8 in

the length is 8+10= 18 in

6 0
3 years ago
Wright an inequality to represent each relationship and solve.
Shkiper50 [21]
I have the exact same question and I tried to look it up on here
8 0
4 years ago
Read 2 more answers
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