Answer:
<u>D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.</u>
Step-by-step explanation:
1. Let's review the information given to us to help Adam to determine where his error is.
A. He completely forgot to include the clothes he bought from Bargains RUS. No, he didn't. It was recorded properly, including the sales tax amount.
B. He made an arithmetic error in the balance column. No he didn't, the balance was calculated correctly after each transaction.
C. He recorded one of his withdrawals in the deposit column. No, he didn't. All of the withdrawals are in the right column.
<u>D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.</u>
Answer:
a) both have same distance
b) second park has a larger area
Step-by-step explanation:
a) park a: circumference is
75+75+30+ pi*30( the diameter of the inward semi circle is 30)
be also has the same perimeter because the diameter of outward semi circle is also 30
b) in the first park, the semi circle area is cut out
in the second its part of the park
Consider such events:
A - slip with number 3 is chosen;
B - the sum of numbers is 4.
You have to count ![Pr(A|B).](https://tex.z-dn.net/?f=Pr%28A%7CB%29.)
Use formula for conditional probability:
![Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.](https://tex.z-dn.net/?f=Pr%28A%7CB%29%3D%5Cdfrac%7BPr%28A%5Ccap%20B%29%7D%7BPr%28B%29%7D.)
1. The event
consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event
is
![Pr(A\cap B)=\dfrac{1}{20}.](https://tex.z-dn.net/?f=Pr%28A%5Ccap%20B%29%3D%5Cdfrac%7B1%7D%7B20%7D.)
2. The event
consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event
is
![Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.](https://tex.z-dn.net/?f=Pr%28B%29%3D%5Cdfrac%7B2%7D%7B20%7D%3D%5Cdfrac%7B1%7D%7B10%7D.)
3. Then
![Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.](https://tex.z-dn.net/?f=Pr%28A%7CB%29%3D%5Cdfrac%7B%5Cfrac%7B1%7D%7B20%7D%20%7D%7B%5Cfrac%7B1%7D%7B10%7D%20%7D%3D%5Cdfrac%7B1%7D%7B2%7D.)
Answer: ![\dfrac{1}{2}.](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D.)
Hey there,
$75 is above $50
Final Bill = $75 - (20% x $75)
= $75 - $15
= $ 60
Hope this helps :))
<em>~Top♥</em>
Answer:
59.0 miles per hour
Step-by-step explanation:
When you have an equation with an absolute value, you must consider two options: one with a positive result and another one with a negative result.
![x-55 = 4.2\\x = 4.2 + 55\\x = 59.2\\\\And\\\\x-55 = -4.2\\x=-4.2 + 55\\x = 50.8](https://tex.z-dn.net/?f=x-55%20%3D%204.2%5C%5Cx%20%3D%204.2%20%2B%2055%5C%5Cx%20%3D%2059.2%5C%5C%5C%5CAnd%5C%5C%5C%5Cx-55%20%3D%20-4.2%5C%5Cx%3D-4.2%20%2B%2055%5C%5Cx%20%3D%2050.8)
In this case you need the maximum safe driving speed which is 59.2 miles per hour