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Lemur [1.5K]
3 years ago
8

9/4 divided by 3/8 PLEASE HELP

Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

6

Step-by-step explanation:

Bad White [126]3 years ago
7 0

Answer:

6

Step-by-step explanation:

9/4 ÷ 3/8

= 9/4 × 8/3

= 72/12

= 6

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The 3 triangles are similar to each other. Find the value of x.
Fed [463]

Answer:

Step-by-step explanation:

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3 years ago
How do i make them into fractions decimals and percentages
Ksivusya [100]
If one of them is wrong it is because it is blury! sorry!

13) 72/100

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4 years ago
What is the solution to the system of equations? Use the substitution method. {y=2x+43x−6y=3 Enter your answer in the boxes
UNO [17]

Answer:

the solution is (-3, -2)

Step-by-step explanation:

Please, separate your equations with a (;) or a (.).  Better yet, write only one equation per line:

y=2x+4

3x−6y=3

Substitute 2x + 4 for y in the second equation:

3x - 6(2x + 4) = 3, or

3x - 12x - 24 = 3

Combining like terms, we get -9x = 27, and so x = -27/9, or x = -3.

Since we know that y=2x+4, we replace x in this equation with -3 and calculate y:

y = 2(-3) + 4 = -2

Then the solution is (-3, -2).

6 0
3 years ago
Find the measure of the arc or angle indicated​
ycow [4]

Step-by-step explanation:

Let O be the center of the circle

We have Angle YOW = 125°

and Angle WOX = 121°.

Therefore Angle YOX = 360° - 125° - 121° = 114°.

(Sum of angles around a point is 360°)

Since Angle at Center = 2 * Angle at Circumference,

Angle YWX

= 0.5 * Angle YOX = 0.5 * 114° = 57°. (A)

6 0
3 years ago
Please HELPPPP me !!!!!
dedylja [7]

Answer:

y = 4x - 3\\Slope \ m_1 = 4

EQUATION OF LINE PERPENDICULAR

Lines \ are \  perpendicular => m_1 \cdot m_2 = -1\\

slope, m_2 = \frac{-1}{4}

equation \ of \ the\ line \ passing \ through \ (-2, 2) \ slope ,m_2 :\\(y - y_2) =m_2(x - x_2)\\ (y - 2) = \frac{-1}{4} (x -(-2))\\\\y - 2 = \frac{-1}{4} (x +2)\\\\y = \frac{-1}{4}x - \frac{1}{2}  + 2\\\\y = \frac{-1}{4}x + \frac{3}{2}

EQUATION OF LINE PARALLEL

Lines \ are \ parallel => m_1 \cdot m_3 = 1\\slope, m_3 = \frac{1}{4}Equation \ of \ the \ line \ through \ (-2, 2) \ and \ slope, m_3:\\(y - y_3) =m_3(x - x_3)\\\\(y-2) = \frac{1}{4} (x - (-2))\\\\y-2 = \frac{1}{4}(x+2)\\\\y = \frac{1}{4}x + \frac{1}{2} +2\\\\y = \frac{1}{4}x + \frac{5}{2}

6 0
3 years ago
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