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2 years ago

6) HELP I got it wrong can someone plz fix it and tell me what I did wrong!

Mathematics

2 answers:

Marianna [84]2 years ago

8 0

The slope is wrong. You go up 6 and over 3 so there for 6/3 which reduces to 2 if you count from the Y point up to the X point you get 6

grigory [225]2 years ago

5 0

Answer:hejdj

Step-by-step explanation:

Hdndjdjd

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How to find gain or loss % when the gain or loss % is not given

g100num [7]

Answer:

Gain = S.P - C.P

Loss =C.P - S.P

where, S.P equals spelling price

and C.P equals cost price

Step-by-step explanation:

Hope it helps

7 0

3 years ago

What is the factorization of 3x2 – 8x + 5?

tatuchka [14]

For this case we must factor the following expression:

$3x ^ 2-8x + 5$

We rewrite the middle term as a sum of two terms whose product is

$a * c = 3 * 5 = 15$

And whose sum is

$b = -8$

These numbers are:

-5 and -3

So:

$3x ^ 2-5x-3x + 5$

We factor the maximum common denominator of each group: $x (3x-5) - (3x-5)$

We take common factor $(3x-5):$

$(3x-5) (x-1)$

Answer:

$(3x-5) (x-1)$

5 0

3 years ago

The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-

Elena-2011 [213]

$y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)$