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topjm [15]
2 years ago
9

I’m need help with the question in general.

Mathematics
2 answers:
navik [9.2K]2 years ago
8 0

Answer:

I Cant  See

Step-by-step explanation:

algol132 years ago
8 0

Answer:

I cant see sorry?

Step-by-step explanation:

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Simplfy <br> 2x+4/-3 = 12
nasty-shy [4]
So you have the equation (2x+4)/-3=12
Multiply by -3 on each side. 
2x+4=-36
2x=-20
x=-10
Hope this helps.
4 0
3 years ago
Find the length and width of 4 different rectangles such that each rectangle has an area of 24 square units. Write the length an
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3 years ago
Concept 10.3: Find the area of the shaded sector. Round to the nearest tenth.
love history [14]

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8 0
3 years ago
Read 2 more answers
Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v
Juliette [100K]

Compute the surface element:

\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}

\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}

So the integral is

\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv

=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)

=\dfrac23(37^{3/2}-1)

4 0
3 years ago
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