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3 years ago

14

The value of your father’s car when bought was $30,000. If it loses 10% of its value every year, how long until the vehicle is o

nly worth $20,000?

1 answer:

Anvisha [2.4K]3 years ago

6 0

Answer:

6.7

Step-by-step explanation:

10% of 30000

10/100 x 30000

0.10 x 30000

=3000

In order to find how long you have to divide 20k with 3k

20000/3000 = 6.66666667

Round it up and you get 6.7

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IRINA_888 [86]

The value for the expression f(-3) for f(x)=9+12x is -27.

f(-3)=9+12(-3)
f(-3)=9-36
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3 years ago

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Answer:

Hello,

10,070

Step-by-step explanation:

100% - 12% = 88% = 0.88

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3 years ago

Anbody know the answer??

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3 years ago

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Answer:

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Step-by-step explanation:

Step one:

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3 years ago

What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

<u>Binomial Series</u>

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$

$\implies \left(\dfrac{120}{6}\right)a^{3}b^3$

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2 years ago