3 years ago

Please help with limits (Precalc)

Mathematics

1 answer:

alexdok [17]3 years ago

5 0

Answer:

option d is correct....

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0.4

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2 years ago

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navik [9.2K]

Answer:

$x=-6$

Step-by-step explanation:

$(\frac{2^{7}}{2^{9}})^{3} \\(\frac{128}{512})^{3} \\(\frac{1}{4})^{3}\\(\frac{1}{4})*(\frac{1}{4})*(\frac{1}{4})\\\frac{1*1*1}{4*4*4} \\\frac{1^{3} }{4^{3} } \\\frac{1}{64} \\2^{x}=\frac{1}{64}\\log 2^x=log\frac{1}{64}\\x*(log(2))=log\frac{1}{64}\\x=\frac{log\frac{1}{64}}{log(2)} \\x=-6$