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3 years ago

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Line segment XY has endpoints X(–10, –1) and Y(5, 15). To find the y-coordinate of the point that divides the directed line segm

ent in a 5:3 ratio, the formula y = (A/A+B) (y2 – y1) + y1 was used to find that y = (5/5+3) (15 – (–1)) + (–1).
Therefore, the y-coordinate of the point that divides XY into a 5:3 ratio is?

2 answers:

Over [174]3 years ago

8 0

Answer:

The y co-ordinate is 9

Step-by-step explanation:

We simplify the expression given by the formula;

$\frac{5}{8}*16-1=9$

alexira [117]3 years ago

8 0

Answer:

The y-coordinate is 9.

Step-by-step explanation:

The given line segment has endpoints X(-10,-1) and Y(5,15).

The formula for finding the y-coordinate of the point that divides the directed line segment in the ratio a:b is

$y=(\frac{a}{a+b} )(y_2-y_1)+y_1$ .

The given ratio is 5:3.

We plug in the values to get

$y=(\frac{5}{5+3})(15-(-1))+(-1)$

We simplify to get;

$y=(\frac{5}{8})(16)+(-1)$

$y=10-1$

$y=9$ .

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<h3>Answer:</h3>

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vfiekz [6]

Answer:

Step-by-step explanation:

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