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jekas [21]
3 years ago
6

Find the solution of this system of equations

Mathematics
2 answers:
Sindrei [870]3 years ago
7 0
I did it using elimination method.

gulaghasi [49]3 years ago
4 0
6x = 90 +3y\\
x - 3y = 50\\\\
-6x+3y=-90\\
\underline{x-3y=50}\\
-5x=-40\\
x=8\\\\
8-3y=50\\
3y=-42\\
y=-14

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What is the scale factor of the dilation when the pre-image is 9 and the image is 24?​
lakkis [162]
<h3>Answer:  8/3</h3>

Explanation:

Divide the image length over the pre-image length to get

24/9 = (8*3)/(3*3) = 8/3

The scale factor is 8/3. This means the image is 8/3 times longer compared to the pre-image.

6 0
3 years ago
Complete the following pattern: 4, 7, 10, 13, 16, 19, ___ .<br> A. 35<br> B.22
scoundrel [369]

Step-by-step explanation:

Simple the pattern is add 3

So next is 22

4 0
3 years ago
Find the values of x and y in the parallelogram.
ValentinkaMS [17]
Answer:
x = 20
y = 8

In a parallelogram, there are always two pairs of equal sides, where in this question:

Side CD = Side BA
Side DA = Side CB

Use this to find x and y.

CD = BA
15 = x - 5
x = 20 (rearranging to find x)

DA = CB
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8 0
2 years ago
A Fraction Number: The sum of the numerator and denominator is 40. if its value is 3/5 after simplifying, what is the fraction b
katrin2010 [14]
Here: Fraction = 3/5
Let, original fraction (before simplifying) = 3x/5x
Then, 3x + 5x = 40
8x = 40
x = 40/8
x = 5

So, 3x = 3(5) = 15 & 5(5) = 25

In short, Your Answer would be 15/25

Hope this helps!
5 0
3 years ago
The value of cos X is<br> 40/41<br> 42/41<br> 9/41<br> 35/41
DIA [1.3K]

Answer:

I think we're probably talking about a right triangle. So just find the adjacent side and the hypotenuse.

Step-by-step explanation:

Once we are considering x \in \mathbb{R}, the range of  \text{cos}(x) is [1, -1]. Therefore, $\frac{42}{41} $ is not true.

In this exercise, we may have

$\text{cos}(x)=\frac{x}{r} =\frac{x}{\sqrt{x^2 +y^2} } $

Considering the trigonometric functions beyond the unit circle.

Or considering the definition in the right triangle:

$\text{cos}(x)=\frac{\text{adjacent}}{\text{hypotenuse}} $

7 0
3 years ago
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