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3 years ago

PLEASE HELP !!!!!!!!!!! WILL MARK BRIANLIEST !!!!!!!!!!!!!

Mathematics

1 answer:

Luden [163]3 years ago

8 0

Answer:

6:9 and 2:3

Step-by-step explanation:

Divide 30:45 by 5 and then divide that answer by 3 for the next one.

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Osvaldo’s teacher asked him to write an equivalent equation for length, l, in terms of perimeter, p, and width, w. He wrote:

Andrej [43]

Answer:

step 2

Step-by-step explanation:

Given

p = 2l + 2w ( subtract 2w from both sides )

p - 2w = 2l ← correct step 1

Now, divide both sides by the multiplier 2

$\frac{p-2w}{2}$ = l

3 0

4 years ago

Read 2 more answers

Find the area of a circle with a circumference of \blueD{18.84}18.84start color blueD, 18, point, 84, end color blueD units.

g100num [7]

Answer:

28.26

Step-by-step explanation:

The circumference of a circle is the distance around the edge of the circle. To find the circumference, we use the formula C = 2πr. The area of the circle is the amount inside the circle and is found using A = πr². Substitute the relevant values in each situation into the formulas to find the circumference and/or area.

Substitute C = 18.84 and solve for r. Then substitute r into the area formula.

C = 2πr

18.84 = 2πr

3 = r

A = πr² = π(3)² = 28.26

8 0

3 years ago

I’ll give you 30 points for this .

Lubov Fominskaja [6]

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4 0

3 years ago

Find an equation of the circle whose diameter has endpoints (1,-4) and (-3,6).

MAVERICK [17]

Answer:

$(x+1)^2+(y-1)^2=58$

Step-by-step explanation:

To find the equation of this circle, we must know the center and the radius.

We can find the radius by dividing the value of the distance formula by 2 (since $r=\frac{d}{2}$ ):

$d=\sqrt{(-3-1)^2+(6-(-4))^2}=\sqrt{116}\\r=d/2=\frac{\sqrt{116}}{2}$

We can then find the center of the circle by averaging the coordinates:

$\frac{1+(-3)}{2}=-1$

$\frac{-4+6}{2}=1$

Then, we substitute these values into the equation of a circle:

$(x-(-1))^2+(y-1)^2=(\frac{\sqrt{116}}{2})^2\\(x+1)^2+(y-1)^2=58$

3 0

4 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

7 0

3 years ago