Answer:
3 and 11
Step-by-step explanation:
Given 2 sides with third side x , then
difference of 2 sides < x < sum of 2 sides , that is
7 - 4 < x < 7 + 4
3 < x < 11
Thus the possible values the third side cannot be are 3 and 11
Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer:
Step-by-step explanation:
Let the smallest number = x
The next number will be x + 1
x + x + 1 = 5
2x + 1 = 5 This is likely the answer to the question although it could be the equation above.
Answer:
See below ~
Step-by-step explanation:
<u>Sin A</u> : opposing side of ∠A / hypotenuse
<u>Sin C</u> : opposing side of ∠C / hypotenuse
<u></u>
<u>Cos A</u> : adjacent side of ∠A / hypotenuse
<u></u>
<u>Cos C</u> : adjacent side of ∠C / hypotenuse
