find the mean, median, and mode of he data set. round to the nearest tenth. 7, 5, 4, 2, 1, 1, 2, 3, 5, 4, 5
SashulF [63]
Hello!
First you need to list the numbers from least to greatest
1, 1, 2, 2, 3, 4, 4, 5, 5, 5, 7
To find the mean you add all the numbers up and divide the sum by the amount of numbers added
1 + 1 + 2 + 2 + 3 + 4 + 4 + 5 + 5 + 5 + 7 = 39
39 / 10 = 3.9
The mean is 3.9
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To find the median you find the number in the middle
The median is 4
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The mode is the number that appears the most
The mode is 5
Hope this helps!
Answer:
if each commercial lasts 1/2 minute how many commercials are there in a 4-hour program?
480
Step-by-step explanation:
4 hours= 240 mins
240/0.5=480
Answer:
B is True
A, C. D are false
Step-by-step explanation:
Given :
Sample size, n = 120
Mean diameter, m = 10
Standard deviation, s = 0.24
Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96
The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.
The population here is N = 10000
To obtain
Confidence interval (C. I) :
Mean ± margin of error
Margin of Error = Zcritical * s/sqrt(n)
Margin of Error = 1.96 * 0.24/sqrt(120)
Confidence interval for the 10,000 ball bearing :
10 ± 1.96 * (0.24) / sqrt(120)
Hence. The confidence interval defined as :
10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.
Answer:
The percentage change from July to November is 67.27 %
Step-by-step explanation:
Given as :
The number of tourists at the beach per weekend in the month of July =
= 55,000
The number of tourists at the beach per weekend in the month of November =
= 18,000
Let the percentage change from July to November = A %
Or, % decrease change =
× 100
So , A % =
- \textrm
}{\textrm
}[/tex] × 100
or, A % =
× 100
Or, A % =
× 100
Or, A = 67.27 %
So percentage change between two months = 67.27 %
Hence The percentage change from July to November is 67.27 % Answer